(2cosx-1)(cos^2x-1)=0

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Solution for (2cosx-1)(cos^2x-1)=0 equation: 


Simplifying
(2cosx + -1)(cos2x + -1) = 0

Reorder the terms:
(-1 + 2cosx)(cos2x + -1) = 0

Reorder the terms:
(-1 + 2cosx)(-1 + cos2x) = 0

Multiply (-1 + 2cosx) * (-1 + cos2x)
(-1(-1 + cos2x) + 2cosx * (-1 + cos2x)) = 0
((-1 * -1 + cos2x * -1) + 2cosx * (-1 + cos2x)) = 0
((1 + -1cos2x) + 2cosx * (-1 + cos2x)) = 0
(1 + -1cos2x + (-1 * 2cosx + cos2x * 2cosx)) = 0
(1 + -1cos2x + (-2cosx + 2c2o2s3x2)) = 0

Reorder the terms:
(1 + -2cosx + -1cos2x + 2c2o2s3x2) = 0
(1 + -2cosx + -1cos2x + 2c2o2s3x2) = 0

Solving
1 + -2cosx + -1cos2x + 2c2o2s3x2 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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